write the nth term of ap -5,-1,3,7
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Find the difference between each value. 7-3, 11-7 ...
For this series the difference is 4.
The nth term is then 4n + or - a constant.
The series is 3, 7, 11.. each of these is 1 below a multiple of 4.
4*1- 1 =3
4*2- 1=7 and so on.
So the nth term would be 4n-1
For this series the difference is 4.
The nth term is then 4n + or - a constant.
The series is 3, 7, 11.. each of these is 1 below a multiple of 4.
4*1- 1 =3
4*2- 1=7 and so on.
So the nth term would be 4n-1
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♠ ANSWER :
A. P. = - 5, - 1, 3, 7.
First term, a 1 = - 5,
Second term, a2 = -1
Common difference , d = a2 - a1 = - 1 - ( - 5)
d = - 1 +5 = 4
nth Term, An = a+ (n + 1 ) d
An = - 5 + ( n + 1 ) 4
An = - 5 + 4n + 4
⏺️An = 4n - 1 .
A. P. = - 5, - 1, 3, 7.
First term, a 1 = - 5,
Second term, a2 = -1
Common difference , d = a2 - a1 = - 1 - ( - 5)
d = - 1 +5 = 4
nth Term, An = a+ (n + 1 ) d
An = - 5 + ( n + 1 ) 4
An = - 5 + 4n + 4
⏺️An = 4n - 1 .
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