Question

write the number of diagonal of a polygon which has number of side As given below
3side
5 side
7 side
please describe​

Answer 1

Hello there!!

3 SIDED: A triangle has zero diagonals. A diagonal connects any two non-consecutive vertices of a polygon. The problem is in a triangle all vertices are consecutive: there are no unconnected vertices.

n(n-3)/2 = 3(3-3/2) = 3*0 = 0

5 SIDED: A regular pentagon has 5 diagonals on the inside of the shape.

The diagonals of any poygon can be calculated using the formula n×  (n-3)/2

where n is the number of sides, in case of a pentagon  which "n" will be 5,

5*(5-3)/2 = 5*(2/2) = 5*1 = 5

7 SIDED: A heptagon has 14 diagonals. The number of diagonals can be found by: n•(n-3)/2.

So in this case :7•(7 - 3)/2 = 7•4/2 = 14 diagonals.

hope it helps!!

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