Write the number of points where f (x) = |x+2|+|x-3| is not differentiable.witg explanation
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Answer:
f (0.5) = (x+2) + (x-3)
Step-by-step explanation:
f (x) = (x + 2) + (x - 3)
f = x + 2 + x - 3
f = 2x - 1
-2x = -1
x = -1/-2
x=0.5
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