Question

Write the number of significant figures in 0.0072m

Answer 1

Answer:

Step-by-step explanation:

How many significant figures are in 0.098000?

By convention, if you write it that way, people will assume there are five significant digits: 98000.

You should be aware, however, that this is merely a convention—the motivation being that there is no good reason for the trailing zeros to be there, except to indicate that they are significant. In this case, it looks unambiguous. However, if you have a value like 98000, rather than 0.098000, how many significant digits are there? (Somewhere between two and five, one imagines.) This is one value of scientific notation: By writing 9.8000×104 (or whatever it happens to be), one indicates exactly how many significant digits there are.

This distinction highlights that what makes the digits significant, in fact, is the source of the value. If you’re measuring the mass of something on a scale, and it measures to the nearest microgram, then that accuracy is the source of the five significant digits (you have 98000 micrograms). If it only measures to the nearest 10 micrograms, then it may output the same digits, but then there are only four significant digits.

This applies as well to values that are derived from measurements by analysis or statistical formulas. There are rules that govern how precision is propagated through addition, multiplication, and other operations; they determine the number of significant digits in the result. The way it’s written is only a convention. Without knowing how the 0.098000 in your question was derived, we can only guess that the value was written in accordance with those rules.

Answer 2

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Here is your answer.

The significant figure of the number 0.0072 m is
$= 7.2 \times 10 {}^{ - 3} \: m$

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