Write the number of zeroes in the end of a number whose prime
factorization is 2^2 x 5^3 x 3^2 x 17.
Answers
Answered by
3
Answer:
2 zeroes are there.
Step-by-step explanation:
2² × 5³ × 3² × 17
= 2² × 5² × 5 × 3² × 17
= 100 × (5 × 9 × 17)
Since hundred is there, so two zeroes
Answered by
3
Answer:
no of zeroes=2
Step-by-step explanation:
2^2 x 5^3 x 3^2 x 17 = 2 × 2 × 5 × 5 × 5 × 3 × 3 × 17
= 4 × 125 × 9 × 17
= 76500
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