Math, asked by Ria6344123, 1 year ago

write the number of zeroes in the end of a number whose prime factorization is 2^2*5^3*3^2*17​

Answers

Answered by shreyaagrawal73
3

2×2×5×5×5×3×3×17=76500

i.e. it has two zeros in its end.

hope it helps you..


Ria6344123: ma ansrZ crct too
shreyaagrawal73: ok
mit45: hy shreya
Answered by pintu9435
0
2×2×5×5×5×3×3×17= 76500

pintu9435: hlo
pintu9435: mere saat chat kar sakti ho
Ria6344123: sry..lil' bc
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