Question

Write the number of zeroes in the end of a number whose prime factorization is 2^2*3^2*5^3*17

Answer 1

Answer: 2

Step-by-step explanation:

2x5=10

Each pair of 2 and 5 will contribute one zero each. There are two such pairs and hence there will be two zeroes

Answer 2

Answer:

2 zeroes  - number of zeroes in the end of a number whose prime factorization is 2^2*3^2*5^3*17

Step-by-step explanation:

To find the number of zeroes at the end of the number formed we first need to find the number.

Performing the operations we have :

2² × 3² × 5³ × 17 = 76500

The number formed by the product of the prime factors above is 76500.

We can now count the number of zeroes at the end of this number.

The number of zeroes at the end of this number are two.

So there are 2 zeroes.