write the number of zeros in the end of a number whose prime factorization is 2^2 × 5^3 × 3^2 × 17.
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1
Answer:
The answer is
Step-by-step explanation:
4×125×9×17
=76500
Answered by
1
we have,
2² × 5³ × 3² × 17
2² × 5² × 5 × 3² × 17
(2 × 5)² × 5 × 3² × 17
(10)² × 5 × 3² × 17
Clearly, there are two zeros at the end of the given number.
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