Math, asked by aadiasuu, 1 year ago

Write the number x in usual form, whose prime factorisation is given below:n=2^7×5^6×13. Also, find the number of zeroes it contains.

Answers

Answered by danielochich
44
x = 2^7×5^6×13
   = 2x2x2x2x2x2x2x5x5x5x5x5x5x13
   = 128x15625x13
   = 26,000,000

It has 6 zeros
Answered by nikitasingh79
54
Given: prime factorization of n : 2^7 × 5^6 ×13
x = 2^7 × 5^6 × 13
= ( 2 x 2 x 2 x 2 x 2 x 2 x 2 ) x ( 5 x 5x 5 x 5 x 5 x 5) x 13
= 128 x 15625 x 13
=2000000 × 13
= 26,000,000
Hence,the number x contains 6 zeroes.

HOPE THIS WILL HELP YOU...
Similar questions