Question

write the outer electronic configuration of 'Ge' using orbital notation method.​

Answer 1

Explanation:

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1

Answer 2

Answer:

The outer electronic configuration of Ge (Germanium) is [Ar] $4 s^{2}, 3 d^{10}, 4 p^{2}$.

Explanation:

Germanium was in the same family with the elements in carbon and silicon. It has four electrons in their outer shell. So the orbital structure for germanium is 2-8-18-4  

Here, $2-1 s^{2}$which indicates that there are 2 electrons in the s subshell and (l=1) with principle quantum number n=2.

$8-2 s^{2}, 2 p^{6}$, which indicates that there are 2 electrons in the s subshell and 6 electron in the p subshell. With the quantum number n=2.

$8-3 s^{2}, 3 p^{6}, 3 d^{10}$ , which indicates that there are 2 electrons in the s subshell 6 electron in the p subshell. and 10 electron in the d subshell with quantum number n=3.

$4- s^{2}, 4 p^{2}$ which indicates that there are 2 electrons in the s subshell and 2 electron in the p subshell. with the quantum number n=4.