Question

Write the physical state of following reaction‐        2 Ag   + 2 HCl     →   2 AgCl    +  H2  ​

Answer 1

Answer:

Correct option is

B

Pt

(s)

∣H

2(g)

,1 bar∣1 M HCl

(aq)

∣1MAg

(aq)

+

∣Ag

(s)

In the given reaction

2AgCl(s)+H

2

(g)(1 Bar)→2HCl(aq)+2Ag(s)

Silver is undergoing reduction (Ag

+

→Ag),

hence it will act as cathode in the following cell.

Pt(s)∣

(anode)

H

2

(g)

,1 bar∣1 M HCl(aq∣∣

(cathode)

1 M Ag

+

(aq)

∣Ag(s)

(i) Thus, since option (a) has KCl which is not present in the cell, it is incorrect.

(ii) Since option (c) has AgCl (s) which does not ionise, it is incorrect.

(iii) Since in option (d), at cathode, Ag is being oxidised to Ag

+

which is not possible, so it is also incorrect.

So option B is only correct among the 4 options.