Question

write the polynomial the product and sum of whose zeroes are -9/2and -3/2 respectively

Answer 1

Sum of zeroes = -9/2
Product of zeroes = -3/2

The required polynomial is :-
» k [x² - (sum of zeroes)x + (product of zeroes)]
» k [x² - (-9/2)x + (-3/2)]
» k [x²+9x/2 - 3/2]

put k=2 to remove the fraction
» 2(x²+9x/2 - 3/2)
» 2x²+9x-3 is required polynomial

Answer 2

sum of zeros = -9/2

product of zeros = -3/2

the required polynomial is

k [ x2 - ( sum of zeros) x + ( product of zeros) ]

k [ x2 - ( -9/2) x (-3/2) ]

k [ x2 - 9x / 2 - 3/2 ]

put k = 2 to remove the fraction

2 [ x2 + 9x/2 - 3/2 ]

2x2 + 9x - 3

it is required polynomial