write the polynomial whose zeros are -3and1
Answers
Answer :
The required polynomial is x² + 2x - 3
Step-by-step explanation :
Given :
The zeroes of the polynomial are -3 and 1
To find :
the polynomial
Solution :
Let α and β are the zeroes of the given polynomial.
⇒ Sum of zeroes = -3 + 1
α + β = -2
⇒ Product of zeroes = (-3) (1)
αβ = -3
The quadratic polynomial is of the form
k [ x² - (sum of zeroes)x + (product of zeroes) ]
where k is any integer
⇒ k [ x² - (-2)x + (-3) ]
⇒ k [ x² + 2x - 3 ]
So, infinite polynomials can be formed with the given zeroes.
Put k = 1, the polynomial is x² + 2x - 3
Put k = 2, the polynomial is 2x² + 4x - 6
Thus, infinite polynomials can be formed.
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#Know more :
- Quadratic polynomial is a polynomial of degree 2.
- General form is ax² + bx + c
- We can find the zeroes by using quadratic formula,
- b² - 4ac is called discriminant (D)
- Based on the value of discriminant, nature of roots is determined.
If D > 0 ; the roots are real and unequal
If D = 0 ; the roots are real and equal
If D < 0 ; the roots are not real i.e., complex roots
Step by step explanation:-
Given that zeros of polynomial are -3&1
To find:-
Polynomial
Required polynomial =
x²-[sum of roots]x + product of roots
Sum of roots = -3 +1
Sum of roots = -2
Product of roots = -3×1
Product of roots = -3
So, Required polynomial is
x² -[Sum of roots]x + product of roots
x² -(-2) x -3
x² +2x -3 is the required polynomial
Veification :-
We have got equation Their roots should b equal to -3&1
x² +2x -3 =0
x² +3x -x -3 =0
x(x+3)-1(x+3)=0
(x +3)(x-1)=0
x = -3,1 hence verified