Question

Write the prime factorisations of the following:

a.128 b.7429​

Answer 1

Step-by-step explanation:

a. We know that the factors of 128 = 1, 2, 4, 8, 16, 32, 64, 128

The product of all the factors = 1 × 2 × 4 × 8 × 16 × 32 × 64 × 128 = 268,435,456

Hence, the product = 268,435,456

b. The factors of 7429 are 1, 17, 19, 23, 323, 391, 437, 7429. Therefore, 7429 has 8 factors.

Answer 2

Step-by-step explanation:

See this attachment

Hope its help..