write the probability of certain and uncertain event
Answers
Hey there !!
Probability
→ Probability is a concept which numerically the degree of certainty of the occurrence of events .
Events
→ The collection of all or some of the possible outcomes is called events .
E.g :- In throwing a coin , H is the event of getting a head . Suppose we throw two coins simultaneously and let E be the event of getting at least one head. Then, E contains HT, TH, HH .
Equally likely events
→ A given number of events are said to be equally likely if none of them is expected to occur in preference to the others .
Probability of occurrence of an event
→ Probability of occurrence of an event E, denoted by P(E) is defined as :
→ P(E) =
Certain events
It is evident that in a single die, we will always get a nimber less than 7 .
So, getting a number less than 7 is a certain event .
P( getting a number less than 7 ) = 6/6 = 1 .
Thus, the probability of a certain event is 1 .
Means P(E) = 1 , when E is a certain event .
Uncertain event
In a single toss of a die, what is the probability of grtting a number 8?
We know that in tossing a coin , 8 will never come up .
So, getting 8 is an uncertain event .
P( getting 8 in a single theow of a die ) = 0/6 = 0 .
Thus, the probability of an uncertain event is zero .
Means, P(E) = 0, when E is an uncertain event .
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#BeBrainly.
Probability
→ Probability is a concept which numerically the degree of certainty of the occurrence of events .
Events
→ The collection of all or some of the possible outcomes is called events .
E.g :- In throwing a coin , H is the event of getting a head . Suppose we throw two coins simultaneously and let E be the event of getting at least one head. Then, E contains HT, TH, HH .
Equally likely events
→ A given number of events are said to be equally likely if none of them is expected to occur in preference to the others .
Probability of occurrence of an event
→ Probability of occurrence of an event E, denoted by P(E) is defined as :
→ P(E) = \bf \frac{ number \: of \: outcomes \: favourable \: to \: E }{ total \: number \: of \: possible \: outcomes }totalnumberofpossibleoutcomesnumberofoutcomesfavourabletoE
Certain events
It is evident that in a single die, we will always get a nimber less than 7 .
So, getting a number less than 7 is a certain event .
P( getting a number less than 7 ) = 6/6 = 1 .
Thus, the probability of a certain event is 1 .
Means P(E) = 1 , when E is a certain event .
Uncertain event
In a single toss of a die, what is the probability of grtting a number 8?
We know that in tossing a coin , 8 will never come up .
So, getting 8 is an uncertain event .
P( getting 8 in a single theow of a die ) = 0/6 = 0 .
Thus, the probability of an uncertain event is zero .
Means, P(E) = 0, when E is an uncertain event .