Question

write the product of the zeros of the polynomial 1 - 2x -3x²​

Answer 1

Answer:

3x²+2x-1=0

3x²+3x-x-1=0

3x(x+1)-1(x+1)=0

(3x-1) (x+1)

: x=1/3

or

x = -1

:

product of zeros

(1/3) (-1)

= -1/3

Answer 2

Answer:

- 1/3

Step-by-step explanation:

1 - 2x - 3xsquare = 0

- 3 x square - 2x + 1 = 0

3 x square + 2x - 1 = 0

3 x square + ( 3 - 1 ) x - 1 = 0

3x square + 3x - 1x - 1 = 0

3x ( x + 1) - 1 ( x + 1 ) = 0

( x + 1) ( 3x - 1 ) = 0

Therefore the required zeros are,

x + 1 = 0. , 3x - 1 = 0

x = -1. , x = 1/ 3

Therefore the required product of zeros is = - 1x 1 / 3

= - 1 / 3