write the products of the following reaction ch3ch2och3 +hi
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Answer:
it is help full
Explanation:
Correct option is
C
CH
3
CH
2
I
CH
3
−CH
2
−O−CH
2
−CH
3
+
excess
2HI
→
ethyl iodide
2CH
3
CH
2
I
+H
2
O
when HI is present in limited quantity CH
3
CH
2
I and CH
3
CH
2
OH both are formed.
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