Question

Write the program in Java to display the first ten terms of the following series:
a) 1,4,9,16,...
b) 1,2,4,7,11,...
c) 3,6,9,12,...

Answer 1

Answer:

a) int num=1, add=3, inc=2;

for (count=0, count<10, count++) {

s.o.p(num);

num = num + add;

add = add + inc;

}

b) int num=1, count=0, add=1, inc=1;

for (count=0, count<10, count++) {

s.o.p(num);

num = num + add;

add = add + inc;

}

c) int num=3, count=0, add=3;

for (count=0, count<10, count++) {

s.o.p(num);

num = num + add;

count = count+1;

}

Explanation:

Note :- There can be various methods of writing the same program.

s.o.p stands for System.out.println

num = starting digit

add = number that is to be added to num at each iteration

inc = number by which add has to increased each time.

like in part 'a', 3 has to be added first, then 5, then 7 and so on.

So Inc is 2. which means that every time 2 more has to be added.

Answer 2

Answer:

1,4,9,16,25,36,49,64,81,100

Explanation:

public class series

{

int k;

public void display()

{

int t=0;

for(k=1;k<=17;k+=2)

t=t+k;

System.out.print(t+" , ");

{

System.out.print("100");

}

}

}