Write the pythagon triplate whose number is 6
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the basis Pythagorean triplet form is (2m,m^2 +1,m^2 -1)
2m= 2(6)=12
m^2+1=6^2+1=36+1=37
m^2-1=6^2-1=36-1=35
the Pythagorean triplet is (12,37,35)
2m= 2(6)=12
m^2+1=6^2+1=36+1=37
m^2-1=6^2-1=36-1=35
the Pythagorean triplet is (12,37,35)
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