Question

write the Pythagorean triplet, whose member are formed by :---
A) 10
b)16​

Answer 1

2M,2M^2+1,2M^-1

1.10
=2M=10
=M=10/2=5

M^2+1
=5^2+1
25+1
=26

M^2-1
=5^2-1
=25-1
24



2.2 M=16
M=16/2
=M=8

M^2+1
=8^2+1
=16+1
=17


M^2-1
=8^2-1
=16-1
=15






HOPE IT WILL HELP YOU DEAR.....