Write the pythagorean triplet whose one member is 14.
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Phythagorean triplets are numbers in form -
2m , m²+1 and m²-1
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So If one of the numbers is 14
let it be 2m.
Then, 2m = 14
or, m = 14/2
or, m= 7
We've got m = 7
So other two numbers are -
m²+1 = 7²+1 = 49+1 = 50
m²-1 = 7²-1 = 49-1 = 48
So, The triplets are 14,48 and 50
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