Question

Write the Pythagorean triplet whose one member is 8 solve the sum

Answer 1

Answer:

Step-by-step explanation:

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

Let 2m = 8

m = 4

m²+ 1 = 4² + 1= 16 + 1 = 17

m²- 1 = 4² - 1 = 16 - 1 = 15

check:

8² + 15² = 64 + 225 = 289 = 17²

Hence, 8, 15 and 17 are the Pythagorean triplets.

Answer 2

Answer:

Pythagorean triplet are 6,8,10

Step-by-step explanation:

8^2 =64

⇒  100−64=36

⇒   square of 36 =6

⇒   square of 100=10

Let Hypotenuse =10            [ Since its greater than 6 and 8  ]

Base =8 and

Perpendicular =6

(Hypotenuse) ^2 =(Perpendicular) ^2 +(Base) ^2 =  [ Pythagoras theorem ]

⇒  (10) ^2 =(6)^2+(8)^2

⇒  100=36+64

⇒  100=100

∴   Pythagorean triplet are 6,8,10      .

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