write the pythagorean triplet whose one number is 8
Answers
Answered by
0
Answer:
It is given that smallest number is 8. So, 2m = 8. Now, second number = m² -1 = 4² – 1 = 15 and, third number = m² + 1 = 4² + 1 = 17. Hence, the triplet is 8, 15 and 17
thank you
Similar questions