Write the quadratic equation for the following:“The age of Ruchi is twice the age of Monika. The
product of their ages will be 160 after four years. Find their present ages.”
Answers
ANSWER:
According to Problem:
Let the age of Monika be x years.
and, Ruchi's age will be 2x years.
Now,
Monika's age after 4 years = x + 4
And Ruchi's age after 4 years = 2x + 4
ATQ,
Product of their ages is 160 after 4 years.
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Divide this quadratic equation by 2
By solving this equation:
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Note: As age cannot be negative, ignore the negative value and take x as 6.
Hence,
Monika's present age = x = 6 years.
Ruchi's present age = 2x = 2 × 6 = 12 years.
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Answered By : MoonGurl01
Given : The age of Ruchi is twice the age of Monika. The product of their ages will be 160 after four years.
To find : Write the quadratic equation . Find their present ages
Solution:
Let say age of monika = M Years
The age of Ruchi is twice the age of Monika.
=> Age of Ruchi = 2 M Years
The product of their ages will be 160 after four years
After 4 years Monika Age = M + 4 years
After 4 years Ruchi age = 2M + 4 Years
Products of age = (M + 4)(2M + 4)
(M + 4)(2M + 4) = 160
=> 2M² + 12M + 16 = 160
=> M² + 6M + 8 = 80
=> M² + 6M - 72 = 0
M² + 6M - 72 = 0 is the required quadratic equation
M² + 6M - 72 = 0
=> M²+ 12M - 6M - 72 = 0
=> M (M + 12) - 6(M + 12) = 0
=> (M - 6)(M + 12) = 0
=> M = 6 ( M = - 12 not possible as age can not be negative )
Monika Age = 6 Years
Ruchi Age = 12 years
M² + 6M - 72 = 0 is the required quadratic equation
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