Question

write the quadratic equation if the sum of the root is -6 an product of the root is 4​

Answer 1

Answer:

required quadratic eq. =

x^2 - x(sum of roots) + (product of roots)

if, s = -6 & p = 4

then eq. will be,

x^2 + 6x - 4

Answer 2

Answer:

The equation will be $x^{2} +6x+4$

Step-by-step explanation:

The values of x that fulfil the quadratic equation ax2 + bx + c = 0 are referred to as the equation's roots. They are the values of the variable (x) that the equation requires. The x-coordinates of the x-intercepts of a quadratic function are the roots of the function. A quadratic equation can only have a maximum of two roots because of its two degree.

The values of the variable that satisfy a quadratic equation are known as its roots. The "solutions" or "zeroes" of the quadratic equation are other names for them.

How many roots the equation has and what kind of roots it has are discussed in the section on the nature of quadratic equation roots. A quadratic equation may have:

1. Two distinct and true roots

2. two intricate roots

three equal and genuine roots (it means only one real root)

Quadratic equation needed: x2 - x(sum of roots) + (product of roots)

If sum = -6 and product = 4, then

then The equation will be $x^{2} +6x+4$

For more details on Essay Writing, https://brainly.in/question/28301617

#SPJ1