Write the quadratic polynomial whose zeroes are (√3+2) and(√3-2).
Answers
Answer:
Answer is p(x)=x^2 - 6x +7
Step-by-step explanation:
The formula is p(x)= x^2 - (alpha + beta)x + (alpha × beta)
alpha+ beta = 3 - √2 + 3 + √2
=3+3 +0
=6
alpha × beta= 3-√2 × 3+√2
=(3-√2)(3+√2)
=3^2 - √2^2
=9-2
=7
p(x)= x^2 - (alpha+beta)x + (alpha × beta)
p(x)=x^2 - (6)x+1
Answer is p(x)=x^2 - 6x +7
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Answer:
Answer. It is given that the zeros of the quadratic polynomial is 2+√3 and 2-√3 . Sum of zeros = (2+√3+2-√3) = 4 .
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