Question

Write the quantum numbers for the 21st electron of Vanadium

Answer 1

Answer:

Explanation:

Valence electrons quantum numbers

n = 3

V 4s2 3d3. l = 2

ml = 0

ms = +1/2

s= 0

p= 1

d= 2. -2. -1. 0. 1. 2

f= 3

Answer 2

The electronic configuration of Vanadium is -

V → [Ar] 3d³ 4s²

Total number of electrons = 23

In the case of Vanadium, electrons are first filled in 4s and then in 3d due to the energy gap. Thus, the 21st electron is the first one to enter the 3d subshell of the atom.

For Vanadium's 21st electron, quantum numbers are -

Principal quantum number = n = 3

Azimuthal quantum number = l = 3 (d subshell)

Magnetic quantum numbers = m = -2 or +2

Spin quantum number = s = -1/2, +1/2

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