Question

write the ratio of K.E and P.E of an electron

Answer 1

Answer:

Explanation:

According to Bohr's theory,

Electrostatic force = centripetal force

K(Ze)e/r² = mv²/r

mv² = K(Ze)(e)/r

∴ Kinetic energy = 1/2 mv² = K(Ze)(e)/2r

And potential energy = F.dr = -K(Ze)(e)/r

so, Total energy = P.E + K.E = -K(Ze)(e)/2r

Kinetic energy of an electron in an orbit , K.E = K(Ze)(e)/2r

Total energy of an electron in an orbit , T.E = -K(Ze)(e)/2r

Hence, Ratio of K.E and T.E ={K(Ze)(e)/2r}/{-K(Ze)(e)/2r} = -1/1

∴ answer = -1 : 1

hope it helps you my lovely dear !!!!!!!!