Math, asked by offsyttsso, 1 year ago

write the rationalising factor of the denominater in 1/√2+√3.

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Answered by reemaanver999
0

Hope this helps... Plz mark as brainliest..!

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reemaanver999: Plz mark as brainliest..!
Answered by Simplebeing
2


 Rationalising \ factor = \frac{ \sqrt{2}-  \sqrt{3}  }{ \sqrt{2}-  \sqrt{3}  } \\\\ \\\\ Solution : \\\\ \frac{1}{\sqrt{2} + \sqrt{3}}   \\\\ \frac{1} {\sqrt{2} + \sqrt{3}}   \ X \ \frac{\sqrt{2} - \sqrt{3}}{\sqrt{2} - \sqrt{3}} \   -----------( rationlising \ denominator) \\\\ \frac{\sqrt{2} - \sqrt{3}}{2 - 3}  \ ----------[ \ (a+b) (a-b) = a^2 - b^2 \ ] \\\\ \frac{\sqrt{2} - \sqrt{3}}{-1} \\\\  \ - ( \sqrt{2} - \sqrt{3} ) \\\\ -\sqrt{2} + \sqrt{3}


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