Write the rationalising factor of the denominator in
1 ÷√2+√3
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1/(√2+√3)
(√2-√3) / (√2+√3)(√2-√3)
(√2-√3) / (√2)²-(√3)²
√2-√3 / 2-3
√2-√3/(-1)
-(√2-√3)/-(-1)
√3-√2/1
=⟩ √3-√2
Hope this helps you
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