WRITE THE REACTION OF ALUMINIUM WITH SODIUM HYDROXIDE SOLUTION.
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2 Al + 2 NaOH + 6 H2O ------> 2Na+ + 2[Al(OH)4] + 3 H2
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2 Al + 2 NaOH + 6 H2O ----> 2 Na+ + 2[Al(OH)4]- + 3 H2 (gas)
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