Chemistry, asked by rajat3395, 1 year ago

Write the relationship between the half life and average life of a radioactive substance

Answers

Answered by smartyyash7
11
• The half-life of a radioactive elementis the amount of time it takes for half of a sample of the element to decay away.

• It is smaller than the mean lifetime by a factor of ln(2), the natural logarithm of 2. The half-life units are time units such as seconds or years
Answered by Swarnimkumar22
25

 \bf \: Radioactive  \: decay  \: is  \: a \:  statistical \\  \bf process, \:  that \:  is,  \: it  \: can \:  not  \: be \:  \\   \bf \: said  \: that  \: which  \: particle \:  of  \: \\  \bf radioactive  \: substance  \: will \\   \bf \: release \:  the \:  particle \:  by  \: decay  \: and \:  \\  \bf  \: d ecay.  \: Thus, \:  the  \: time  \: of  \: decay \\   \bf\:  of  \: the  \: nucleus \:  can \:  be \:  anything  \: between \:  zero \:  and  \: \\  \bf  \: infinite,  \: hence \:  the  \: average  \: age \:  of \:  \\  \bf all  \: nuclei  \: is  \: called \:  median \:  \\   \bf \: age.  \: Display  \: it \:  from \: ( \tau )  \\  \\  \underline {\bf Middle  \: of \:  the \:  radioactive} \\  \underline{ \bf substance  \: is  \: equal  \: to \:  the} \\   \underline{ \bf \:  \: inversion  \: of  \: decay \:  determines}  \\  \\ mens \:  \boxed{ \tau =  \frac{1}{ \lambda} }

\bold{\huge{\underline{Relation\:Between\:Half\:Life\:and\:Average\:life}}}

The half life of Radioactive substance

T \:  =  \frac{0.6931}{ \lambda}  \\  \\  \implies0.6931 \times  \frac{1}{ \lambda}

But,

 \bf \: Average \: life  \implies \tau =  \frac{1}{ \lambda}  \\  \\ so \:  \:  \:  \:  \:  \bf \:   T  = 0.6931  \tau

Means- Half life (T) = 0.6931 × Average life

Or \:  \:  \:  \:  \:  \:  \:  \:  \tau = ( \frac{1}{0.6931} ) \times T

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \implies1.443 \: T \:

 \boxed{ \bf \: Average \:  life = 1.443  \times Half-life }

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