Math, asked by vsreeja1980, 2 months ago

write the sequence of 3digit natural number which leave a remainder 3 on division by 8 ?

Answers

Answered by Kiranmarkad23

1

answers-70821

Step-by-step explanation:

All these numbers are 101,108, 115, ..., 997

997=101+(n−1)7

⇒ n=129

so S=

2

129

[101+997]=70821.

Answered by sachinarjunsaha

1

Answer:

107,115,123,131,139,147,..995

Step-by-step explanation:

hope it'll understandable

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