Question

write the sequence of the first ten cubes of natural numbers​

Answer 1

Answer:

Sequences and Series

Series  of the cube numbers

There is a series to each sequence and this is the sequence of the partial sums.  

For cube numbers this is the sequence  sn= 1³+2³+3³+...+n³.  

1³+2³+3³+...+n³=[n(n+1)/2]² is given.

The sequence of the cube numbers is also an arithmetic series of third order. A figure follows to explain this.

In every new row you find the difference of two numbers a row higher.  

The feature is that you reach a constant difference 6 after three steps.  

HOPE IT HELPS YOU

Step-by-step explanation:

Answer 2

1^3=1

2^3=8

3^3=27

4^3=64

5^3=125

6^3=216

7^3=343

8^3=512

9^3=729

10^3=1000