Question

write the sin A cot A tan A in the form of cot A​

Answer 1

Answer:

Correct option is

B

sinA=cot2A+11secA=cotAcot2A+1tanA=cotA1

We have 

1]cosec2A−cot2A=1

⇒cosec2A=1+cot2A

⇒(cosecA)2=cot2A+1

⇒(sinA1)2=cot2+1

⇒(sinA)2=cot2A+11

⇒sinA=±cot2A+11

We reject the negative value of sinA for acute angle A. Therefore sinA=cot2A+11

Step-by-step explanation:

make me brainlist

please give me some thanks