Write the slope and y- intercept of the line x /3+ y/4=1
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According to y=mx+c
Slope=m=-4/3
and y-intercept =c=4
x/3+y/4=1
(4x+3y)/12=1
4x+3y=12
3y=-4x+12
y=-4/3x+12/3
So, y=-4/3x+4
So, slope= -4/3
y-intercept= 4
Slope=m=-4/3
and y-intercept =c=4
x/3+y/4=1
(4x+3y)/12=1
4x+3y=12
3y=-4x+12
y=-4/3x+12/3
So, y=-4/3x+4
So, slope= -4/3
y-intercept= 4
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