write the smallest digit and the greatest 6 digit in the blank space of the each of the following numbers so that the number formed is divisible by 3 a - -------- 6724 b- 4765 ----- 2
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a) __ 6724
Number is divisible by 3 if the sum of digits is multiple of 3.
Sum of digits = 6 + 7 + 2 + 4 = 19
Smallest digit that we can add to the sum to make it multiple of 3 is 2.
Doing so, we get sum of digits = 19 + 2 = 21 which is the multiple of 3.
Greatest digit that we can add to the sum to make it multiple of 3 is 8.
Doing so, we get sum of digits = 19 + 8 = 27 which is the multiple of 3.
(b) 4765 __ 2
Number is divisible by 3 if the sum of digits is multiple of 3.
Sum of digits = 4 + 7 + 6 + 5 + 2 = 24
Smallest digit that we can add to the sum to make it multiple of 3 is 0.
Doing so, we get sum of digits = 24 + 0 = 24 which is the multiple of 3.
Greatest digit that we can add to the sum to make it multiple of 3 is 9.
Doing so, we get sum of digits = 24 + 9 = 33 which is the multiple of 3.
Number is divisible by 3 if the sum of digits is multiple of 3.
Sum of digits = 6 + 7 + 2 + 4 = 19
Smallest digit that we can add to the sum to make it multiple of 3 is 2.
Doing so, we get sum of digits = 19 + 2 = 21 which is the multiple of 3.
Greatest digit that we can add to the sum to make it multiple of 3 is 8.
Doing so, we get sum of digits = 19 + 8 = 27 which is the multiple of 3.
(b) 4765 __ 2
Number is divisible by 3 if the sum of digits is multiple of 3.
Sum of digits = 4 + 7 + 6 + 5 + 2 = 24
Smallest digit that we can add to the sum to make it multiple of 3 is 0.
Doing so, we get sum of digits = 24 + 0 = 24 which is the multiple of 3.
Greatest digit that we can add to the sum to make it multiple of 3 is 9.
Doing so, we get sum of digits = 24 + 9 = 33 which is the multiple of 3.
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