Question

Write the smallest number is divisible by both 306 and 657.

Answer 1

Answer:

to find the number take LCM of both 306 and 657

306=2*3*3*17

657=3*3*73

LCM=2*3*3*17*73=22338

hope its right answer..and helpful

Answer 2

Smallest number is divisible by both 306 and 657 is 22338

Solution:

Given that,

We have to find the smallest number is divisible by both 306 and 657

Step 1:

Find the LCM of 306 and 657

List all prime factors for each number.

Prime Factorization of 306 is:     2 x 3 x 3 x 17

Prime Factorization of 657 is:   3 x 3 x 73

For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.

2, 3, 3, 17, 73

Multiply these factors together to find the LCM

LCM = 2 x 3 x 3 x 17 x 73 = 22338

Thus the smallest number is divisible by both 306 and 657 is 22338

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