write the structure of HNO3 and find the oxidation state of different elements.....
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Answer:
oxidation states:
H=+1
O=-2
N=-((-2×3)+(+1))=+5
Explanation:
oxidation state of H is +1 (known to us)
oxidation state of O is -2 (known to us)
let oxidation state of N = x
x+3*(-2)+(+1)=0
x-6+1=0
x-5=0
x=+5(this is the answer)
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