Write the structure of the alkene formed by dehydrohalogenation of 1-bromo-1-methylcyclohexane with alcoholic koh.
Answers
Answered by
46
Answer is in the attachment:
Attachments:
Answered by
11
Hey dear,
● Answer -
[Refer to the diagram for structure of product.]
● Explaination -
- Alkanes on dehydrogenation with sodium ethoxide (in ethanol) gives alkenes.
- In these reactions, halogen atom from α-C and H-atom from β-C is removed.
- 1-bromo-1-methylcylohexane on dehydrogenation with sodium ethoxide in ethanol gives 1-methylcyclohex-1-ene.
C6H10(Br)(CH3) ---> C6H9CH3 + HBr
Hope this helps you...
● Answer -
[Refer to the diagram for structure of product.]
● Explaination -
- Alkanes on dehydrogenation with sodium ethoxide (in ethanol) gives alkenes.
- In these reactions, halogen atom from α-C and H-atom from β-C is removed.
- 1-bromo-1-methylcylohexane on dehydrogenation with sodium ethoxide in ethanol gives 1-methylcyclohex-1-ene.
C6H10(Br)(CH3) ---> C6H9CH3 + HBr
Hope this helps you...
Similar questions