A radioactive material is reduced to 1/16 of its original amount in 4 days how much material should one begin with so that 4*10
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solution ;
radioactivity decay formula is
N=Noe^-λt.....(1)
λ= radioactivity Decay constant
Νo=initial amount of material
Ν=material letf after t time
given data
Ν=1/16Νo t= 4 days
putting values in equation 1
16=e^4λ ⇒λ=In 16/4=In 2...(2)
now second case
let initial amount of material Mo Kg
given Ν=4*10^-3 kg t= 6 days
putting values in 1
4*10^-3=Moe^-6λ o=256 *10^-3kg
putting λin equation 2
4*10^-3=Moe^-6In2
⇒4*10^-3=Moe^-In2^6
⇒4*10^-3=Moe^-In64= Mo/64
⇒M
so initial amount required 256*10^-3 kg
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