write the sum and product of the zeros of the 3x^2-4x+7
Answers
Answered by
12
Hi ,
Compare 3x² - 4x + 7 with ax²+bx +c
we get ,
a = 3 , b = -4 , c = 7,
1 ) sum of the zeroes= -b/a
= - ( -4 3 )
= 4/3
2 ) product of the zeroes = c/a
= 7/3
I hope this helps you.
: )
Compare 3x² - 4x + 7 with ax²+bx +c
we get ,
a = 3 , b = -4 , c = 7,
1 ) sum of the zeroes= -b/a
= - ( -4 3 )
= 4/3
2 ) product of the zeroes = c/a
= 7/3
I hope this helps you.
: )
Answered by
16
HELLO DEAR,
GIVEN THAT:-
3x² - 4x + 7
where,
a = 3 , b = (-4) , c = 7
alpha + beta = -b/a
= alpha + beta = -(-4)/3
= alpha + beta = 4/3
and,
alpha * beta = c/a
= alpha * beta = 7/3
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN THAT:-
3x² - 4x + 7
where,
a = 3 , b = (-4) , c = 7
alpha + beta = -b/a
= alpha + beta = -(-4)/3
= alpha + beta = 4/3
and,
alpha * beta = c/a
= alpha * beta = 7/3
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
:-)
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