D o thissssss......with a note... How will do this??
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Answered by
1
hey there,
here is ur answer
as the above mentioned triangle being a scalene trinagle with sides
13,14,15
there is a formula
where
whole root of
s(s-a)(s-b)(s-c)
where s is the semiperimeter and
it is the sum of all sides divided by 2
![13 + 14 + 15 \div 2 13 + 14 + 15 \div 2](https://tex.z-dn.net/?f=13+%2B+14+%2B+15+%5Cdiv+2)
![42 \div 2 42 \div 2](https://tex.z-dn.net/?f=42+%5Cdiv+2)
which is
21
now applying the formula
we get,
21(21-13)(21-14)(21-15) whole root
21(8)(7)(6)
which is
7056 whole root
84cm^2
a b and c are the three different sides
hope this helps u
@@@@
sid071
here is ur answer
as the above mentioned triangle being a scalene trinagle with sides
13,14,15
there is a formula
where
whole root of
s(s-a)(s-b)(s-c)
where s is the semiperimeter and
it is the sum of all sides divided by 2
which is
21
now applying the formula
we get,
21(21-13)(21-14)(21-15) whole root
21(8)(7)(6)
which is
7056 whole root
84cm^2
a b and c are the three different sides
hope this helps u
@@@@
sid071
Answered by
1
Given,
sides of triangle are 13cm, 14cm and 15 cm
s(semi-perimeter) = (13+14+15)/2
= 21 cm
area of triangle using Heron's formula is
![\sqrt{s(s - a)(s - b)(s - c)} \sqrt{s(s - a)(s - b)(s - c)}](https://tex.z-dn.net/?f=+%5Csqrt%7Bs%28s+-+a%29%28s+-+b%29%28s+-+c%29%7D+)
![\sqrt{21(21 - 13)(21 - 14)(21 - 15)} \sqrt{21(21 - 13)(21 - 14)(21 - 15)}](https://tex.z-dn.net/?f=+%5Csqrt%7B21%2821+-+13%29%2821+-+14%29%2821+-+15%29%7D+)
![\sqrt{21 \times 8 \times 7 \times 6} \sqrt{21 \times 8 \times 7 \times 6}](https://tex.z-dn.net/?f=+%5Csqrt%7B21+%5Ctimes+8+%5Ctimes+7+%5Ctimes+6%7D+)
![\sqrt{3 \times 7 \times 2 \times 2 \times 2 \times 7 \times 2 \times 3} \sqrt{3 \times 7 \times 2 \times 2 \times 2 \times 7 \times 2 \times 3}](https://tex.z-dn.net/?f=+%5Csqrt%7B3+%5Ctimes+7+%5Ctimes+2+%5Ctimes+2+%5Ctimes+2+%5Ctimes+7+%5Ctimes+2+%5Ctimes+3%7D+)
= 2×2×3×7 sq.cm
=84 sq.cm
sides of triangle are 13cm, 14cm and 15 cm
s(semi-perimeter) = (13+14+15)/2
= 21 cm
area of triangle using Heron's formula is
= 2×2×3×7 sq.cm
=84 sq.cm
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