write the sum of 1st nt terms of an AP
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sum of first n term is n/2(a+l)
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Let the first term be ‘a’, the last term be ‘l’,the common difference be ‘d’ and the number of terms be ‘n’.
Therefore,sum of the 1st nth terms of an AP=n/2(a+l)or n/2{2a+(n-1)d}
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Therefore,sum of the 1st nth terms of an AP=n/2(a+l)or n/2{2a+(n-1)d}
PLEASE MARK ME AS THE BRAINLIEST ONE MATE.
THANK YOU
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