Question

Write the value of 2.303RT/F at 250C in Nernst equation​

Answer 1

Answer:

Nernst equation is a general equation that relates the Gibbs free energy and cell potential in electrochemistry.

It is very helpful in determining cell potential, equilibrium constant etc. At standard temperature T = 298 K, the 2.303RTF, term equals 0.0592 V.

Answer 2

The value is 0.0592.

Explanation:

To find the value of the given expression, let us first write all the required values.

R $= 8.314 JK^{-1} mol^{-1}$

T $= 25 \degree C = 25 + 273 = 298 K$

F $= 96487 Cmol^{-1}$

Now, the expression is $\frac{2.303RT}{F}$

On substiti\ution of the values, we obtain,

    $\frac{2.303RT}{F}$ $=\frac{2.303\times 8.314\times 298}{96487}$

$=\frac{5705.84}{96487}$

$= 0.0592$

Hence the value of 2.303RT/F at 25 degrees Celcius is 0.0592 in the Nernst equation.