Math, asked by gpsr8107, 1 year ago

write the value of cos^-1 (-1/2)+2sin^-1 (1/2)

Answers

Answered by ASIMOV
3
cos⁻¹ (-1/2) = 120 degrees sin⁻¹(1/2) = 30 degrees 
Therefore, cos^-1 (-1/2)+2sin^-1 (1/2) = 120 + 2(30) = 180 degrees 
Answered by UnknownDude
0

 { \cos }^{ - 1} ( -  \frac{1}{2} ) =  \frac{2\pi}{3} or \:  \frac{5\pi}{3}
 { \sin }^{ - 1} ( \frac{1}{2} ) =  \frac{\pi}{6} or \:  \frac{5\pi}{6}
So there will be 4 solutions
The first will be
 \frac{2\pi}{3}  +  \frac{2\pi}{6}  =  \pi
The second will be
 \frac{5\pi}{3}  +  \frac{2\pi}{6}  = 2\pi
The third will be
 \frac{2\pi}{3}  +  \frac{5\pi}{3}  =  \frac{7\pi}{3}
The fourth will be
 \frac{5\pi}{3}  +  \frac{5\pi}{3}  =  \frac{10\pi}{3}

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