Math, asked by healthtipsyou821, 11 months ago

Write the value of cot^2 A - 1/sin^2 A

Answers

Answered by zvedy
3
cot^A-1/sin^2A
=(cos^2A/sin^2a)-1/sin^2A
=cos^2A-1/sin^2A ( sin^2A+cos^2A=1)
=-sin^2A/sin^2A
=-1
Answered by sathwikganti2311
4

Cot^2A -1/sin^2A

=Cos^2A/Sin^2A-1/sin^2A

=(Cos^2A-1)/Sin^2A

=-sin^2A/Sin^2A

= -1

Similar questions