Write the value of k for which the sum of zeros of yhe polynomials x^2+kx+3 is 4
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Let the Zeroes be X and Y
Sum of zeroes = X+Y = 4(given)
Sum of zeroes = -b/a = -k
So by equating both we get -k=4
hence k=-4
Sum of zeroes = X+Y = 4(given)
Sum of zeroes = -b/a = -k
So by equating both we get -k=4
hence k=-4
Harjot1011:
it is a property that sum of roots is equal to -(cofficient of x) ÷ constant term .......in an quadratic equation
yes bro I know that -b/a that means -k/a=4 they given a=2 so k=-8
sum =-b/a and product is c/a
where is a given as 2????are you mad
i thought that xsquare into 2
sry for wasting your time
thats ok bro....
my self pandu studying 8th class
and i am harjot studying in 12th preparing iir
iit
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