Math, asked by Parthasaha8985, 1 year ago

Write the value of ∫secx(secx+tanx)dx

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Answered by utkarsh016

0

multiply secx with secx+tanx now it will become sec^2x and secxtanx and
integration is sec^2x is tanx and secxtanx is secx so answer is tanx +secx +c

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