Question

Write the zeros of the polynomial $x^{2}-x-6$

Answer 1

SOLUTION :  

GIVEN : f(x) = x² -x -6

By splitting the middle term ,  

f(x) = x² -3x +2x - 6

= x(x - 3) + 2(x -3)

= (x + 2) (x - 3)

On putting f(x) = 0 ,  

(x + 2) (x - 3) = 0

x + 2 = 0   or  x -3 = 0

x = -2  or  x = 3  

Hence, the Zeroes of given polynomial f(x) = x² -x -6 is - 2 & 3.  

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Answer 2

Hey mate here is your answer ⤵⤵⤵⤵

Given p (x)=$x^{2}-x-6$

$\implies x^{2}-x-6=0$

$\implies x^{2}+2x-3x-6=0$

$\implies x (x+2)-3 (x+2)=0$

$\implies (x+2)(x-3)=0$

$\implies x+2=0\:\: or x-3=0$

$\implies x=-2\:\: or x=3$

Hence- 2 and 3 are roots of the given equation

❤hope it helps you ❤

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